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x^2+3x+2/3=0
We multiply all the terms by the denominator
x^2*3+3x*3+2=0
Wy multiply elements
3x^2+9x+2=0
a = 3; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·3·2
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{57}}{2*3}=\frac{-9-\sqrt{57}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{57}}{2*3}=\frac{-9+\sqrt{57}}{6} $
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